8x^2+44x+104=8+4x^2

Solution for 8x^2+44x+104=8+4x^2 equation:

8x^2+44x+104=8+4x^2

We move all terms to the left:

8x^2+44x+104-(8+4x^2)=0

We get rid of parentheses

8x^2-4x^2+44x-8+104=0

We add all the numbers together, and all the variables

4x^2+44x+96=0

a = 4; b = 44; c = +96;
Δ = b2-4ac
Δ = 442-4·4·96
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-20}{2*4}=\frac{-64}{8}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+20}{2*4}=\frac{-24}{8}
=-3
$